5 a day math

This worksheet is from CorbettMaths . I will put the reference to the website at the bottom of this page.

Question 1

1)The first step to working this out is to turn the mixed number to a improper fraction ( It is when the denominator is bigger then the numerator) .Multiply 1 by 3 which will give us 3 . Then i add 2 and 3 which is 5 . That then gives us the new numerator . I have now turned this mixed number into a improper fraction .

2)The second step to working out this problem is actually adding both fraction . I will be adding the proper fraction with the improper fraction .I have to change both of the denominator of these 2 fractions . I have to change both of the denominator to 33 since it fits in both 11 and 3 . This means that the numerator will also have to change . So for 7/11 i will multiply the numerator by 3 which is 21 and for 5/3 i will multiply the numerator by 11 which is 55 . Then i will add both new numerator which will be 76 but the denominator will stay as 33 .

4) The last step to solving this problem is turning this improper fraction into a mixed fraction . I need to first find the a number i can multiply to denominator which will give me a number close to numerator . In this case i can multiply 33 by 2 which gives me 66 . Next i need to know how much we need to add to 66 to get to 76 which is 10 . Now i have turned this improper fraction into a mixed number .

The answer will be 2¹⁰⁄₃₃

Question 2 and 3

Question 4

1)I know that all the angles in a pentagon add up to 540 . So i will add up all the angles and make it equal 540 to make an equation . It will look like this x + 10 + 2X + 10 + x + 10 + x + 20 + 2X = 540 . Next step is to simplify this equation . To do this i will add up all the x together,so i will add x + 2X + x + x + 2X which is leave me with 7X . Then i wil do this for the numbers which will give me 50 . This leaves the equation with 7X + 50 = 540

2)Second step is to solve this equation and find out what x is . I will first have to get rid of the 50 by doing 540 – 50 which will give me 490 . That will leave me with 7X = 490 . The last step is to do 490 divide by 7 which will give me 70 . That leave me with x = 70 .

3)The next step is to solve all of the angles . Which will tell me how much each angles are .

5)Now that i know how much each angles are i can be able to see which angle is the largest angle and i see that it is 150 that is the largest.

Question 5

I didn’t understand this question so this is a topic i need to go over .

Question 6

I didn’t understand this question so this is a topic i need to cover .

reference to the website:

corbettmaths.com/5-a-day/gcse/

corbettmaths.com/2016/10/26/january-answers/

corbettmaths.com/wp-content/uploads/2021/07/Jan-FP_Part4.pdf

corbettmaths.com/wp-content/uploads/2021/07/Jan-4-FP-Ans.pdf


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